(PHP 4 >= 4.0.0)
in_array -- Return TRUE if a value exists in an array
Description
bool in_array (mixed needle, array haystack [, bool
strict])
Searches haystack for needle and returns
TRUE if it is found in the array, FALSE otherwise.
If the third parameter strict is set to TRUE then the
in_array() will also check the types of the
needle in the haystack.
Note: If needle is a string, the comparison is done in a case-sensitive
manner.
Note: In PHP versions before 4.2.0 needle was not allowed to be an
array.
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Example 1. in_array() example
$os = array ("Mac", "NT", "Irix", "Linux");
if (in_array ("Irix", $os)) {
print "Got Irix";
}
if (in_array ("mac", $os)) {
print "Got mac";
}
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The second condition fails because in_array() is case-sensitive, so the program
above will display:
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Example 2. in_array() with strict example
<?php
$a = array('1.10', 12.4, 1.13);
if (in_array('12.4', $a, TRUE))
echo "'12.4' found with strict check\n";
if (in_array(1.13, $a, TRUE))
echo "1.13 found with strict check\n";
?>
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This will display:
1.13 found with strict check
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Example 3. in_array() with an array as needle
<?php
$a = array(array('p', 'h'), array('p', 'r'), 'o');
if (in_array(array ('p', 'h'), $a))
echo "'ph' is found\n";
if (in_array(array ('f', 'i'), $a))
echo "'fi' is not found\n";
if (in_array('o', $a))
echo "'o' is found\n";
?>
// This will output:
'ph' is found
'o' is found
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See also array_search().
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