As said before, references aren't pointers. That means, the following construct won't do
what you expect:
function foo (∓$var)
{
$var =∓ $GLOBALS["baz"];
}
foo($bar);
|
What happens is that $var in foo will be bound with $bar in
caller, but then it will be re-bound with $GLOBALS["baz"]. There's no way to bind
$bar in the calling scope to something else using the reference mechanism, since $bar
is not available in the function foo (it is represented by $var, but
$var has only variable contents and not name-to-value binding in the calling symbol
table).
